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2x^2+9x-893=0
a = 2; b = 9; c = -893;
Δ = b2-4ac
Δ = 92-4·2·(-893)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-85}{2*2}=\frac{-94}{4} =-23+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+85}{2*2}=\frac{76}{4} =19 $
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